Please help with calculus!?

you know the acceleration due to gravity is

-32 feet per second

then the velocity function is the anti derivative of that

v(t) = -32 t

(there is no '+c' in this function since the initial velocity is 0)

then the position function is the anti derivative of that.

s(t) = -16t^2 + c

we set this to zero and put in 9.2 for t

-16(9.2)^2 + c = 0

solving you find c = 1354.24

and this is the height of the building.

This is actually a physics question.

d = 1/2at^2

a = -9.8m/s^2

t = 9.2 s

d = 1/2 x -9.8m/s^2 x 9.2^2s^2

d = 414.736 meters

The building is 414.736 meters tall.

Maybe you are supposed to use calculus for this - if so, hopefully someone else can add some input.

I have forgotten almost everything I knew about calculus.

I'd need a few hours to refresh!