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Let A and B be events in a sample space S such that P(A) = 0.4, P(B) = 0.6, and P(A intersection B) = 0.21. Fi?
Let A and B be events in a sample space S such that P(A) = 0.4, P(B) = 0.6, and P(A intersection B) = 0.21. Find the probabilities below.
(a) P(A|B)
(b) P(B|A)
1 Answer
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- 1 decade agoFavorite Answer
It must be noted that P(AB) = P(BA). Order of intersection of events is irrelevant, the intersection will be the same.
(a) P(A|B) = P(AB)/P(B) = .21/.6
(b) P(B|A) = P(BA)/P(A) = P(AB)/P(A) = .21/.4
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