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What initial speed must the top be given in order to spin for at least 1 minute?
A certain top will remain stable (epright) at angular speeds at or above 3.5 rev/s. The top slows due to friction at a rate of 1.3 rad/s^2. What initial speed (in rad/s and rev/s) must the top be given in order to spin for at least 1 minute?
I know that the answer is 100 rad/s but i just don't know how to get there. I'm assuming its a fairly simple problem, but I'm still troubled by how to calculate it. Help me please? my teacher hasn't even gone over this.
2 Answers
- kuiperbelt2003Lv 71 decade agoFavorite Answer
the angular acceleration of an object can be described via
angular acceleration=(change in angular velocity)/time
ang accel = (final ang vel - initial ang vel)/time
the ang accel = -1.3 rad/s/s (note the minus sign)
let's convert 3.5 rev/s to rad /s
3.5 rev/s = 3.5 rev/s x 2pi rad/ rev x 1 min/60s = 0.37rad/s
so, for the object to be in motion for a minute, losing speed at the rate of 1.3 rad/s/s and remaining above 0.37rad/s, the initial speed is
initial ang vel = final ang vel -(-1.3rad/s)x 60 s
initial ang vel = 0.37rad/s + 78rad/s = 78.37 rad/s
this is the same as 748.8rev/min
- WaheedLv 61 decade ago
final angular velocity wF = 3.5 x 2 pi = 21.991 rad/ sec
time = t = 60 sec
angular acceleration = - 1.3 rad / sec^2
Initial angular velocity = vI
final angular velocity = Initial angular velocity + angular acceleration x time
21.991 = vI - 1.3 x 60
vI = 99.991 rad /sec ans