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Sonny
Lv 4
Sonny asked in Science & MathematicsPhysics · 1 decade ago

What initial speed must the top be given in order to spin for at least 1 minute?

A certain top will remain stable (epright) at angular speeds at or above 3.5 rev/s. The top slows due to friction at a rate of 1.3 rad/s^2. What initial speed (in rad/s and rev/s) must the top be given in order to spin for at least 1 minute?

I know that the answer is 100 rad/s but i just don't know how to get there. I'm assuming its a fairly simple problem, but I'm still troubled by how to calculate it. Help me please? my teacher hasn't even gone over this.

2 Answers

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  • 1 decade ago
    Favorite Answer

    the angular acceleration of an object can be described via

    angular acceleration=(change in angular velocity)/time

    ang accel = (final ang vel - initial ang vel)/time

    the ang accel = -1.3 rad/s/s (note the minus sign)

    let's convert 3.5 rev/s to rad /s

    3.5 rev/s = 3.5 rev/s x 2pi rad/ rev x 1 min/60s = 0.37rad/s

    so, for the object to be in motion for a minute, losing speed at the rate of 1.3 rad/s/s and remaining above 0.37rad/s, the initial speed is

    initial ang vel = final ang vel -(-1.3rad/s)x 60 s

    initial ang vel = 0.37rad/s + 78rad/s = 78.37 rad/s

    this is the same as 748.8rev/min

  • Waheed
    Lv 6
    1 decade ago

    final angular velocity wF = 3.5 x 2 pi = 21.991 rad/ sec

    time = t = 60 sec

    angular acceleration = - 1.3 rad / sec^2

    Initial angular velocity = vI

    final angular velocity = Initial angular velocity + angular acceleration x time

    21.991 = vI - 1.3 x 60

    vI = 99.991 rad /sec ans

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