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A Norman Window with Maximum Light?

I thought I knew how to do this problem, but the answer in the back of the book disagrees.

A Norman window has the shape of a rectangle surmounted by a semicircle. If the rectangle is made of clear glass while the semicircle is made of colored glass which transmits only half as much light per square unit as the clear glass does, what are the dimensions of the window that will admit the most light for a given perimeter. Solve for the width of the window and the height of the rectangular portion of the window in terms of the perimeter.

Let:

r = radius semicircle

2r = width window

h = height rectangular portion of window

P = perimeter window

A = area window

L = amount of light admitted by window

3 Answers

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  • 1 decade ago
    Favorite Answer

    i = incident light per unit area of the window

    As = Area of semicircle = (1/2)pi*r^2

    Ls = light admitted by semicircle = As*i/2 = (1/4)pi*r^2*i

    Ar = area of rectangle = 2*r*h

    Lr = light admitted by rectangle = Ar*i = 2*r*h*i

    L = Lr + Ls = 2*r*h*i + (1/4)pi*r^2*i

    P = pi*r + 2*(r + h)

    h = (P - pi*r - 2*r)/2 = [P - r(pi + 2)]/2

    Since "i" is just some constant I can set it equal to 1 (it comes out anyway when you take the derivative and set it equal to 0 for the maximum L).

    L = r*(P - pi*r - 2*r)+ (1/4)pi*r^2

    L = P*r - (3/4)pi*r^2 - 2*r^2

    dL/dr = 0 = P - (3/2)pi*r - 4*r

    r = P/[4 + (3/2)pi] = 2*P/[8 + 3*pi]

    Width = 2*r = 4*P/[8 + 3*pi] = 0.23*P

    Height = [P - r(pi + 2)]/2 = [P - 2*P(pi + 2)/(8 + 3*pi)]/2

    Height = (P/2)[1 - 2*(pi + 2)/(8 + 3*pi)] = 0.205*P

    My width agrees with that other answer.

  • Anonymous
    5 years ago

    there's a much less complicated way, whether it seems that that some "wager & verify" may be the thank you to bypass (except you be responsive to 3 calculus). i could %. some lengths and widths of the window to confirm what is going to maximize the component to the rectangle, then compute the component to the semi-circle in keeping with my effects. the component to the circle is a function, the bigger it is the greater mild will are available in.

  • 1 decade ago

    What I get is 2r = 4P / (3π + 8)

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