Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Parametric Equations?
For the curve with parametric equations
x = a[t – sin(t)]
y = a[1 – cos(t)]
find the following quantities.
(a) The area bounded by the x-axis and one loop of the curve
(b) The length of one loop
(c) The area of the surface of revolution obtained by rotating one loop about the x-axis
(d) The coordinates of the centroid of the area in (a)
1 Answer
- rozeta53Lv 61 decade agoFavorite Answer
Parametric Equations of Cycloid:
x = a[t – sin(t)] ==> dx/dt=a[1-cos(t)]
y = a[1 – cos(t)] ==> dy/dt=a*sin(t)
(a) and (b)
http://en.wikipedia.org/wiki/Cycloid#Area
(c)
A = 2π ∫[0,2π] y√[(dx/dt)²+(dy/dt)²] dt =
2πa² ∫[0,2π] [1-cos(t)]√[(1-cos(t))²+sin²t] dt =
2πa² ∫[0,2π] [1-cos(t)]√[2-2cos(t)] dt =
2πa² ∫[0,2π] √2[1-cos(t)]^(3/2) dt =
2πa² ∫[0,2π] √2[2sin²(t/2)]^(3/2) dt =
8πa² ∫[0,2π] sin³(t/2) dt =
-16πa² ∫[0,2π] [1-cos²(t/2)] d[cos(t/2)] =
-16πa²[cos(t/2)-cos³(t/2)/3] [t from 0 to 2π] =
-16πa²(-1 + 1/3 -1 + 1/3) = 64πa²/3
(d) Let the area bounded by the x-axis and one loop of the curve be A1=3πa² and let the centroid be at C(π,Y), then
Y = {∫[0,2π] xy (dx/dt) dt} / A1 =
Probably it's easier to find Y by using Pappus-Guldinus centroid theorem
http://en.wikipedia.org/wiki/Pappus's_centroid_the...
In this case you have to calculate the volume of the body of revolution obtained by rotating one loop about the x-axis by
V = π ∫[0,2π] y² (dx/dt) dt = πa³ ∫[0,2π] [1 - cos(t)]³ dt =
πa³ ∫[0,2π] [1 - 3cos(t) + 3cos²t - cos³t] dt =
πa³ ∫[0,2π] [1 + 3cos²t] dt =
πa³ ∫[0,2π] [1 + 1.5 + 1.5cos(2t)] dt =
πa³ ∫[0,2π] 2.5 dt = 5π²a³
According to the second Pappus-Guldinus theorem
V = 2πY * A1
5π²a³ = 2πY * 3πa² ==>
Y = 5a/6
The centroid is at C(π, 5a/6).