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? asked in Science & MathematicsPhysics · 1 decade ago

Can you figure out how to do this physics problem?

A rotating door is made from 4 glass panes. The mass of each pane is 85 kg. The distance from the axis of rotation to the outer edge is 1.2 m. A person pushes the outer edge of one pane with 68 N of force. (perpendicular to the plane) What is the door's angular acceleration rate?

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  • Anonymous
    1 decade ago
    Favorite Answer

    Iσ = Γ

    Where

    σ = angular acceleration

    I - Moment of inertia

    Γ= Torque

    Your torque is 68*1.2=81.6 Nm

    The tricky part is the moment of inertia

    You can model the door as 2 thin rods of mass 85 kg and length 2.4m spinning about their centers.

    The moment of inertia of a single such rod is:

    1/12 * M * L^2

    We have two of them so we can use the formula

    1/6 * M * L^2 = 1/6 * 85 * 2.4^2 = 81.6 kgm^2

    σ = 81.6 / 81.6 = 1 radians/s^2

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