help on simple math?? confused?

2( 4x - 3) - x = 4x - 5

=>8x - 6 - x = 4x - 5

=> 7x - 6 = 4x -5

arranging like terms one side

=> 7x - 4x = -5 +6

=> 3x = 1

=> x = 1/3

Hi:

2(4x-3)-x=4x-5 - original equations

(8x-6)-x = 4x-5 - Multiplication

8x-x-6 = 4x- 5 - gouping like terms together

7x - 6 = 4x- 5 - Addition

7x - 6+6 = 4x -5+6 - Adding the additive inverse of a number to both sides of the equation to move it to the other side of it

7x = 4x + 1 - Addition

7x-4x = 4x +1 - 4x - Adding the additive inverse of a coefficient to both sides of the equation to move it to the other side of it

3x = 1 - Addition

1/3 * 3x = 1* 1/3 - Multiplying the reciprocal of a coefficient to both sides of the equation to solve for x

x = 1/3 - Multiplication

Proof

2(4x-3)-x=4x-5 - Original equation

2(4(1/3) - 3 ) - 1/3 = 4(1/3) - 5 - Substitution of x with 1/3

8(1/3) - 6- 1/3 = 4/3 - 5 - Multiplication

8/3 - 6 - 1/3 = 4 /3 - 5 - Multiplication again

8/3-1/3 -6 = 4 /3 - 5 - Grouping like terms

7/3 - 6 = 4 /3 - 5 - Addition

7/3 - 18/3 = 4/3 - 15/3 - converting 6 to 18 /3 ( remember 6 * 3 /3 = 18/3) and 5 to 15/3 ( 5*3= 15)

-11/3 = 4 /3 - 15/3 - Addition

-11/3 = -11/3 - Addition again

-3 2/3 = - 3 2/3 - Division

It checks and equals

I hope this helps.

2(4x-3)-x=4x-5

Expand the brackets on the left.

8x - 6 - x = 4x - 5

Isolate for x.

8x - x - 4x = -5 + 6

3x = 1

Divide both sides of the equation by the coefficient of x.

(3x)/3 = 1/3

x = 1/3

guy above me forgot to subtract by X, yea the answer is 1/3

2(4x-3)-x = 4x-5

8x-6-x = 4x - 5

7x - 6 = 4x - 5

3x - 6 = -5

3x = 1

x = 1/3

x =1/3 is correct.

expand: 8x -6 - x =4x -5

7x - 6 = 4x -5

3x = 1

x =1/3

8 x -6 - x - 4x +5= 0

3 x -1 = 0

3x = 1

x = 1/3

2(4x - 3) - x = 4x - 5

Expand the bracketed term:

8x - 6 - x = 4x - 5

Simplify LHS:

7x - 6 = 4x - 5

Subtract 4x from both sides:

3x - 6 = -5

Add 6 to both sides:

3x = 1

Divide both sides by 3:

x = 1/3

2(4x-3)-x=4x-5

apply distribution on the left

8x - 6 -x = 4x - 5

subtract 4x from both sides

3x - 6 = -5

add 6 to both sides

3x = 1

divide by 3

x = 1/3

follow PEMDAS

Parenthesis

Exponents

Multiplication

Divition

Addition

Subtraction

2(4x-3)-x=4x-5

since 4x-3 are 2 diff terms

you multiply by 2

8x-6-x=4x-5

then you simplify the x on the left side

7x-6=4x-5

how you want the numbers to one side and the x to the other

you subtract 4 from both sides and you get

3x-6=-5

then you add 6 to both sides

3x=1

then you divide everything by coefficient the number next to x

x=o.3333333333

now all together :)

2(4x-3)-x=4x-5

8x-6-x=4x-5

7x-6=4x-5

-4x -4x

-----------------------

3x-6=-5

+6 +6

--------------------

3x=1

--- ---

3 3

------------

x=1/3 or o.3333333333333

Go to www.wolframalpha.com and enter "solve 2(4x-3)-x=4x-5"

It gives lots, including x=1/3.