Geometry Isosceles triangle question.?

An isosceles triangle is a triangle that has 2 sides and 2 angles the same length.

Area of Triangle: 1/2 x Base x Height = Area

Substituting in the value 1/2 x (14 ft) x Height = 110 ft2

Height = 220/14 = 15.7

If you draw an isosceles triangle with base of 14 ft with the height of 15.7 ft. (draw the perpedicular line from the top of the triangle to the base, that line should be 15.7 ft long) Now you have 2 right triangles.

Pythagorean Theory stated that any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).

The theorem can be written as an equation: A2 + B2 = c2

A = 14 ft x 1/2 (half of the base)

B = 15.7 ft (the height)

I think you can take it from here. Good luck!

Half the base = 7 ft

Area = ½ * base * height

Let h = height then ½ * 7 * h = 110

h = 220/7

Now use Pythagoras' theorem to find the slant height = d

d² = (220/7)² + 7²

d = √1036.755

d = 32.2 ft to the nearest tenth of a foot

tch.....I'm not doing your hw. Isosceles has 2 equal sides so............