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ayuda porfavor en derivadas con fracciones?
y= (3x^2- 6) / (2x+1)
1 Answer
- 1 decade agoFavorite Answer
Ok amigo tu derivada se trata de un cociente y si recuerdas la fórmula dice asi:
d (u / v) v u'- uv'
... = _________
dx v^2
Por tanto:
(2x+1) (6x) -(3x^2-6) (2)
y'= ____________________
( 2x-1)^2
(12x^2+6x) -( 6x^2-12)
y'=________________________
( 2x-1)^2
y'= 12x^2+ 6x - 6x^2+12
__________________
( 2x-1)^2
y'= 6x^2+6x+12
__________
(2x+1)^2
Espero ayudarte . ¡¡suerte!!!
