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- 1 decade agoFavorite Answer
you need a common denominator, (x+1)(x+2) in this case...
2(x+2)+3(x+1)
------------------
(x+2)(x+1)
distribute those terms in the numerator
2x+4+3x+3
-------------
(x+2)(x+1)
combine like terms
5x+7
------------
(x+2)(x+1)
foil the denominator
5x+7
------------
x^2+3x+2
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