Write an equation of the line containing the given point and parallel to the given line.?

Since the line is parallel to the given line, the slopes of both lines are the same.

To find the slope, put 2x-7y=3 into slope intercept form:

-7y=-2x+3

y=(2/7)x -(3/7)

Now that you have the slope, put the slope. along with (6,-8) into point slope form and simplify:

y-k = m(x-h)

y+8 = (2/7)(x-6)

y+8=(2/7)x - (18/7)

y=(2/7)x - (74/7)

MIss Kristin

Okay so you need a line parallel to 2x - 7y = 3

rearrange it in terms of y to find the slope: -7y = -2x + 3 --> y = 2/7x -3/7

Okay now you know the slope is 2/7; parallel lines have the same slope, so your answer should be in the form of y = 2/7x + b

Plug in the coordinates (6, -8) into the equation and solve for b and theres your final answer

first simplify the preliminary equation to the y=mx+b form. y=(9/4)x-(7/4) the "m" fee is the slope of the line. in view that your line is meant to be parallel it needs to have an equivalent slope. So your equation is y=(9/4)x+c the place "c" is a relentless which you don't know yet. to discover "c" we plug the coordinates of your element into the 2nd line equation. -3=(9/4)3+c and remedy algebraically. you may get: y=(9/4)x-(15/4) in case you desire decimals it may be y=2.25x-3.seventy 5 stable good fortune!