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Help with maths please?
I have confused myself on this,
could you please help me?
Prove that
(n+3)^2 - (n-2)^2 = 5(2n+1)
3 Answers
- 1 decade agoFavorite Answer
(n+3)^2 - (n-2)^2 = 5(2n+1)
(n^2+6n+9)-(n^2-4n+4)=(10n+5)
n^2+6n+9-n^2+4n-4=10n+5
10n+5=10n+5
hope u understood
- Graeme RLv 41 decade ago
LHS = (n+3)^2 - (n-2)^2
= (n^2 + 6n + 9) - (n^2 - 4n + 4)
= n^2 + 6n + 9 - n^2 + 4n - 4
= 10n + 5
= 5(2n + 1)
= RHS
- 1 decade ago
(n + 3)^2 - (n - 2) ^ = n^2 + 6n + 9 - (n^2 -4n + 4) = 6n + 4n + 9 - 4 = 10n + 5 = 5(2n + 1)
