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I need help with this probability problem, please?
A bag contains several marbles. Some are red, some are white, some are blue. The probability of of drawing a red marble is 1/6 and the probability of drawing a white marble is 1/3.
What is the probability of drawing a blue marble?
What is the smallest number of marbles that could be in the bag?
Could the bad contain 48 marbles? If so, how many of each color?
If the bag contains 4 red marbles and 8 white marbles, how many blue marbles does it contain?
Thanks so much!
3 Answers
- 1 decade agoFavorite Answer
1. The probability of drawing a blue marble 3/6 or 1/2
2. The smallest number of marbles that can be in the bag is 6
3. Blue=24 marbles Red=8 marbles White=16 marbles
4. The bag will contain 12 blue marbles
Source(s): High school geometry student - 1 decade ago
Probabilities can be used as ratios so 1/6th of the total are red, 1/3rd of the total are white that means the rest of the whole (total of 1) must be blue or (1- 1/6 - 1/3) = 1/2.
The smallest number is the least common denominator for 6, 3, and 2 which is 6. (1 red, 2 white, 3 blue).
If the total is 48 you have 8 (48/6) red, 16 (48/3) white, and 24 (48/2) blue.
If you have 4 red, 8 white, you will have 12 blue. This is because the total is 24 = (4*6) or (8*3) and then 24/2 is 12.
