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i need some help in stats pleasee?
A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.
(a) How many different combinations of 3 cans could be selected?
Number of different combinations _____i got this to be 2024
(b)
What is the probability that the contaminated can is selected for testing?
Probability____ i cant get this one
1 Answer
- peabodyLv 71 decade agoFavorite Answer
a) 24C3 = 24!/21!3! = 24*23*22/6 =2024
b) Pr ( 2 perfect , 1 contaminated )
= 23C2 * 1C1 / 24C3
= 23*22/2 * 1 / 2024
= 251 /2024