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mypetispig83
mypetispig83 asked in Science & MathematicsMathematics · 1 decade ago

How to integrate this? 3/sqare_root_of(4-x^2)?

3 Answers

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  • Tomato
    1 decade ago
    Favorite Answer

    INT [3/sqrt(4-x^2)] dx

    = 3 INT [1/sqrt{4(1-(x^2)/4)}] dx

    = 3 INT [1/{sqrt(4)*sqrt(1-(x/2)^2)}] dx

    = (3/2) INT [1/sqrt(1-(x/2)^2)] dx

    = 3 arcsin(x/2) + C

  • Jas
    1 decade ago

    int 3 / sqrt [(2)^2 - x^2 ] = 3 arcsin [x/2] + c

  • spiffin456
    Lv 7
    1 decade ago

    Make the substitution x=2sin(theta)

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