mypetispig83

INT [ 1/ {2+ sqrt(x)} ] dx

Let u= sqrt(x) , du = 1/(2*sqrt(x));

INT [ 1/ (2+u) ] 2(sqrt(x)) du

INT [ 1/ (2+u) ] 2u du

INT [ 2u/ (2+u) ] du

2 INT [ 1- (2/(2+u)) ] du

2 [u - 2 ( ln |2+u| )] + c

2[ sqrt(x) - 2 ( ln |2+ sqrt(x)| ) ] + c <<<===

but the answer is

∫ f dx = 2*sqrt(x)-4*log(sqrt(x)+2)+4

http://www.numberempire.com/integralcalculator.php...

Which components does POP and MDF consist of?

INT 3e^(2x) + 2/(25+x^2) dx

= 3 e^(2x)/2 + 2 [ (1/5) * arctan (x/5) ] + C

= (3 e^(2x))/2 + [(2 * arctan(x/5) )/ 5 ] + C <====

INT [sin(3x)]^3

according to the Integral Table (61)

http://www.solvemymath.com/online_math_calculator/...

= -3 cos(3x)/4(3) + cos 3(3x) /12(3) + C

=-3 cos(3x)/12 + cos(9x)/36 + C <--

but when using u-substitution,

INT [sin(3x)]^2 * sin(3x) dx

INT [1-(cos(3x))^2)] * sin(3x) dx

let u = cos(3x)

-(1/3)du = sin(3x)

-(1/3)INT [1-u^2] du

INT (-1/3) + (u^2)/3 du

-u/3 + (u^3)/9 + c

= -(1/3)*[cos(3x)] + [cos(3x)]^3/9+ c <==

[e^(x) 10^(x)] / ln 10 + C

INT [1/ sqrt(3-t^2) ] dt

=INT [1/{sqrt(3) * sqrt(1- (t^2)/3)} dt

=1/sqrt(3) INT [1/( sqrt(1- (t/3^(1/2))^2 ) ] dt

={1/sqrt(3)} arcsin (t/sqrt(3))

:(

[log5(8)*log2{sqrt(10)}] / log25{10}

log a 81^2 / log a 27

= log a (81^(2) / 27)

= log a 243

Can it be simplified anymore? How to simplify?

y = 2 tan^(-1) 3x, find dy/dx

..........................................

y/2 = tan^(-1) 3x

tan y/2 = 3x

sec^(2) y/2 . dy/dx = 3

dy/dx = 3/(sex^(2) y/2)

dy/dx = 3/(1+tan^(2) y/2)

dy/dx = 3/(1+(3x)^2)

dy/dx = 3/(1+9x^2) <=== (Check my answer pls)

Z = [A\ (B + C D\ ) + (AC\)\ ]\

\ means 'bar'.

i.e. Z is equal to (A-bar (B + C D-bar)+ (A C-bar)-bar) the whole bar

My solution:

Z = (A\ (B+CD\) + (AC\)\ )\

= (A\ (B+CD\))\ . (AC\)\\

= (A\\ + (B+CD\)\ ) . (AC\)

= (A + (B\.(CD\)\) ) . (AC\)

= (A + (B\. (C\+D)) . (AC\)

= (A + B\C\ + B\D) . (AC\)

= AC\ + AB\C\ + AB\C\D

= AC\ (1 + B\ + B\D)

= AC\ <==

1st question.

Design a 555 free-running oscillator to produce an approximate square wave at 40 kHz. C should be kept at 500 pF or greater.

Answer:

(Ra = 1k, Rb = 10k, C = 1800 pF).

2nd question:

A 555 oscillator can be combined with a J-K flip-flop to produce a perfect (50% duty cycle) square wave. Modify the circuit of question 1 to include a J-K flip-flop. The final output is still to be a 40kHz square wave.

I wonder if they wear or not because if i become a monk, i really need to wear one.

I don't know. The exam is very near and I have been studying well. So I don't want to see the book again. Could you help me so that i wanna revise again and stop keep answering?

It's a miniature camcorder(very tiny so that it can't be seen with naked eyes) which will record your daily activities. The camcorder will also record voice with date and time so that you can easily trace back your forgotten things in the past.

It's like your eyes but one benefit over what a pair of eyes can do is ability to see around you as well.

Everything in the past will be recorded and you could always see what was happening before whenever you wish.

I think it can benefit in many ways.

In a test, half of a class of 40 students scored 80 marks while of the remaining students scored 70 marks and the rest scored 20 marks. Which of the following statements is true?

(a) The mean and the median are the same.

(b) The mean and the mode are the same.

(c) The mean is less than the median.

(d) The mean is greater than the median.

Could you please explain to me how you get (c) mean<median?

There were 10 different Mathematics books in the library.

(i) In how many different ways can the books be distributed equally among 5 friends?

(ii) How many ways can the 10 books be put into 5 piles of 2 each on the table?

(iii) If one student were to get 1 book, another to get 2 books, the third to get 3 books, the forth 4 books and the fifth nothing, how many ways can you distribute the 10 books?

The answer is....

(i)10C2 x 8C2 x 6C2 x 4C2 x 2C2 = 113400

(ii) 113400 / 5! = 945

(iii)10C1 x 9C2 x 7C3 x 4C4 x 5! = 1512000

But how come question one and two are not same? Why do i need to divided by 5!?

and I am confusing question 3 also.

(Teach me if you can....)

#1. how to make friends at Y!answer

#2. how to make friends at facebook

#3. how to deal with ppl

#4. understanding ppl behaviors

#5. what is love which ppl believe?

#6. why ppl are so foolish in certain ways

#7. why some ppl are so nosy and

#8. why some ppl are so jealous

#9. why i am wasting time here writing nonsenses

#10. why i am boring ......>>>go back to #1

have you ever wondered that you are talking to robots at Y!answer?