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mypetispig83
mypetispig83 asked in Science & MathematicsMathematics · 1 decade ago

Could you solve e^2t - 14 e^-2t - 5 = 0 ?

Update:

Can you explain how to solve this question,pls?

e^(2t) - 14e^(-2t) -5

Thank you.

4 Answers

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  • Moise Gunen
    Lv 7
    1 decade ago
    Favorite Answer

    y = e^2t

    y -14/y-5 =0

    y^2 -5y -14=0

    (y-7)(y+2) =0

    e^2t = 7 ; 2t =ln(7) ; t = (1/2) ln(7)

    e^2t = -2 no solutions

    Answer

    t = (1/2)ln(7)

  • Jerome J
    Lv 7
    1 decade ago

    e²t – 14 eˉ²t – 5 = 0

    e²t – 14 eˉ²t = 5

    t = 5/(e² – 14 eˉ²)

  • Jack B
    1 decade ago

    Nope, I couldn't.

  • PinkPanther
    1 decade ago

    Yes, I could. Thanks for asking.

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