easy ten points...................?

For distances, use the Distance Formula

D = sqrt( (y2 - y1)^2 + (x2 - x1) ^2)

In this case, D = sqrt ( 1/3^2 + 1/2^2 )

D = sqrt( 1/9 + 1/4 )

D = sqrt( 13 / 36 )

In simplest form, D = sqrt(13) / 6

Midpoint.. just average the x's and the y's.

x = (1/2 + 1) / 2 = 3/4

y = (1 + 2/3) / 2 = 5/6

midpoint = (3/4, 5/6)

midpoint is 3/4, 5/6

distance is 5/6

Well...haha...do you expect me to do your homework for you???

But Ill answer it still becuase Im bored

What you need is the Distence Formula D= (Square Root) of (X2-X1)[squared]+(Y2-Y1)[Squared]

So D = [Square Root] of (1 - .5) [Squared] + (2/3 -1) [Squared]

D= [Square Root] (.5) [Squared] + (-1/3) [squared]

D= [Square Root] (.25) + (.10)

D = [Square Root] .35

D = .591 (13/6 as a graphable answer)

that is the rough answer... I had to convert 2/3 into a decimal... and since its a repeating one..just made it 0.66