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Please find the area of the surface by rotating around the curve?
Find the area of the surface obtained by rotating the curve x = 1+2y^2 from y=1 to y = 2 about the x-axis.
Please help please!
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- GusBsAsLv 61 decade agoFavorite Answer
dS = 2 π y dL
dL = √(dx²+dy²) = √(16 y² + 1) dy =>
S = 2 π ∫(from 1 to 2) y √(16 y² + 1) dy
u = 16 y² + 1
du = 32 y dy
=>
S = 2 π (1/32) ∫(from 17 to 65) √u du =
= (π/16) (2/3) [65^(3/2) - 17^(3/2)] =
= (π/24) [65^(3/2) - 17^(3/2)]
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