How do you solve 4x-5/x+3 + x-6/x+3?

can't solve, as it is not an equation, it can be simplified.

very ambiguous, I'll guess it as:

(4x–5)/(x+3) + (x–6)/(x+3)

combine

(4x–5+x–6)/(x+3)

(5x–11)/(x+3)

.

Please be more clear with your question.

You can't solve this. Its an equation not an expression. (unless you meant that plus sign to be an equal sign)

Use order of order of operations to simplify. unless there are parenthesis.

1. If the problem is 4x-5/x+3+x-6/x+3, then work with parenthesis first (except there are none here), then deal with exponents (again, non here), then multiply and divide, and finally add or subtract.

So here is what this would look like with parenthesis: (4x) - (5/x) + (3) + (x) - (6/x) + 3. Gather like terms and simplify: (-11/x) + (5x) +(6).

2. If you are simplifying (4x-5)/(x+3) + (x-6)/(x+3), just combine it into a single fraction: ((4x-5)+(x-6))/(x-3). then combine like terms in the numerator: (5x-11)/(x+3).

3. If you are solving (4x-5)/(x+3) = (x-6)/(x+3), then you can multiply both sides by (x+3) to cancel the (x+3) on each side in the denominator. then you are left with 4x-5=x-6. Gather like terms and you get: 3x=-1. Solve and x=-1/3

4. If you are solving (4x)-(5/x)+3 = (x) - (6/x) + (3), (which you are probably not), gather like terms. Subtract 3 from both sides, then subtract 3 from both sides, and add (5/x) to both sides. You get 3x = -(1/x). Simplify to get the quadratic: 3x^2 + 1 = 0. You solve and get the imaginary solutions: x = plus or minus i√(3)/3.

since the denominator is the same, you just add the numerator so it would be

(4x-5) + (x-6) / x+3

then, you since u are adding, you would add the like terms.

you add 4x to x and get 5x.

you add -5 to - 6 and get -11

so your new answer would be 5x-11/x+3

(4x-5)/(x+3)+(x-6)/x+3) LCD is (x+3)

=[(4x-5)+(x-6)]/(x+3)=

=(4x-5+x+6)/(x+3)=

=(5x+1)/(x+3)