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Physics problem help please? Energy problem!?
Im stuck on this one physics problem, need all work to it so i can get ready for my test. Thanks so much :] 10 points
Chimpo the chimp, with a mass of 80 kg, runs and grabs a tire swing with a mass of 20 kg and both swing up to height of 2 m. How fast was chimpo running when he grabbed the tire?
4 Answers
- ?Lv 41 decade agoFavorite Answer
Its quite simple
Chimpo has Kinetic energy when he reaches the tire, and chimpo and the tire have P)otential energy when they have risen to the height of 2metres
Energy cannot be destroyed only converted
So total KE of chimpo = total PE of chimpo and the tire
0.5 x 80 v^2 = (80 + 20) x 10 x 2
40 x v^2 = 2000
V^2 = 2000/40 = 50
v = sqrt 50 = 7.07 ms is Chimpo's velocity
- 1 decade ago
Using conservation of energy, you get that Ek=Ep (Kinetic energy= potential energy)
1/2mv^2 = mgh
1/2 x 80 x v^2 = (80+20) x (-9.8) x 2
v^2 = 100 x (-9.8) x 2 x 2/80
v^2 = 49
v = √49 = 7 m/s
That's your answer!
By the way the value of g is 9.8 not 10!
- Anonymous5 years ago
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- jeffreyLv 71 decade ago
Let
Po = initial momentum of Chimpo
P = final momentum of (Chimpo + tire)
Then
(1) ..... Po = Mc*Vo
where Mc = mass of Chimpo, Vo = initial speed of Chimpo
(2) ..... P = ( Mc + Mt ) * Vct
where Mt = mass of tire, Vct = initial speed of Chimpo and tire
By conservation of linear momentum (Po = P)
(3) ..... Mc*Vo = ( Mc + Mt ) * Vct
Now
(4) ..... Eo = (0.5)*( Mc + Mt ) * Vct^2 = initial energy of Chimpo
and tire at bottom of swing
(5) ..... E = ( Mc + Mt )*g*H = final energy of Chimpo and tire at top of swing
where H = 2.0 m
By conservation of energy (Eo = E)
.......... (0.5)*( Mc + Mt ) * Vct^2 = ( Mc + Mt )*g*H
(6) ..... Vct^2 = 2*g*H
From (3)
(7) ..... Vct = Mc*Vo / ( Mc + Mt )
Substituting (7) in (6)
.......... ( Mc^2)*(Vo^2) / [ ( Mc + Mt )^2 ] = 2*g*H
.......... Vo^2 = 2 * g * H * [ ( Mc + Mt )^2 ] / ( Mc^2)
(8) ..... Vo = SQRT { 2 * g * H * [ ( Mc + Mt )^2 ] / ( Mc^2) }
Substituting the values
.......... 2 * g * H = 2 * (9.8) * (2.0) = 39.2
.......... [ ( Mc + Mt )^2 ] / ( Mc^2) = [ ( 80 + 20 )^2 ] / [ ( 80 )^2) ] = 1.5625
.......... Vo = SQRT { ( 39.2 ) * ( 1.5625 ) } = 7.826
.......... 7.8 m/s = speed of Chimpo when he grabbed the tire