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how do i intergarte tan^2 x and cos ^ 2 x?
i need to have you show me all the steps
3 Answers
- Engr. RonaldLv 71 decade agoFavorite Answer
∫tan^2(x)dx
recall trigonometric Identity
note tan^2(x)=sec^2(x)-1
so
=∫(sec^2(x)-1)dx
=tan(x)-x+C answer//
∫cos^2(x)dx
note using the Multiple-Measure Identites.
...............1+cos(2x)
cos^2(x)=----------------
....................2
................cos(2x)
=1/2∫dx +∫ ------------dx
....................2
....x......sin(2x)
=-----+ ------------+C
....2.......2(2)
......x......sin(2x)
=----------+----------+C answer//
.....2............4
- MathematishanLv 51 decade ago
tan ² x = sec² x -1
Integral [ sec²x - 1] dx = tan x - x + constant
cos ^ 2 x = {1 + cos 2x]/2
integral {[1 + cos 2x]/2} = (1/2) [x + (1/2) sin 2x] + constant