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how do i intergarte tan^2 x and cos ^ 2 x?

i need to have you show me all the steps

3 Answers

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  • 1 decade ago
    Favorite Answer

    ∫tan^2(x)dx

    recall trigonometric Identity

    note tan^2(x)=sec^2(x)-1

    so

    =∫(sec^2(x)-1)dx

    =tan(x)-x+C answer//

    ∫cos^2(x)dx

    note using the Multiple-Measure Identites.

    ...............1+cos(2x)

    cos^2(x)=----------------

    ....................2

    ................cos(2x)

    =1/2∫dx +∫ ------------dx

    ....................2

    ....x......sin(2x)

    =-----+ ------------+C

    ....2.......2(2)

    ......x......sin(2x)

    =----------+----------+C answer//

    .....2............4

  • 1 decade ago

    tan ² x = sec² x -1

    Integral [ sec²x - 1] dx = tan x - x + constant

    cos ^ 2 x = {1 + cos 2x]/2

    integral {[1 + cos 2x]/2} = (1/2) [x + (1/2) sin 2x] + constant

  • ?
    Lv 5
    1 decade ago

    tan^2x=sec^2x-1

    cos^2x =(1/2)+(1/2)cos2x

    that is all you need.

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