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What is the pH of a .005M acetic acid solution that is 8.2 percent ionized?
1 Answer
- Anonymous1 decade agoFavorite Answer
percent ionized means the concentration of [H+] when talking in terms of acid (it will be [OH-] when talking in terms of a base)
So you must find out what is 8.2% of 0.005M
.082*(.005M) = 4.1E-4M
Now you know the [H+] concentration, so you take the -log of [H+]
pH = -log (4.1E-4) = 3.3872....but with sig figs it will be 3.39 (sig figs for pHs start after the decimal...it is tricky and most teachers will try to trick you on that)
Source(s): Majoring in Chemistry