Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Probability question?
The question says: You are going to toss a coin repetedly in sucessive trials until you get a head for the first time, and then you are going to stop the experiment. Assuming that the coin is unbalanced with P(head)=1/5.
(1) Express the event "at least 4 tosses are required" in terms of the outcomes
(2)Compute the probabilities P ("at least 4 tosses are required before the experiment terminates")
(3) Explain why the probability calulated in (4) is large
Please help!
3 Answers
- PaulaLv 71 decade agoFavorite Answer
1. If at least 4 tosses are required, then the first 3 tosses are tails. So the event is P(1st 3 tosses are tails). I think that is what they mean.
2. P(1st 3 tosses are tails) = p(tail) x p(tail) x p(tail) = 4/5 x 4/5 x 4/5 = (4x4x4) / (5x5x5) = .... (I'll let you work out the actual number)
3. It is high because tails are much more likely than heads, so there is a fairly good chance that the first three tosses will be tails.
- 1 decade ago
I'm trying to figure out the same question. I would think it would be 1/2*1/2*1/2*1/2=P(TTTH). because if 4 tosses are required, no matter how many time you toss it the probability each time is going to be 1/2 right?
- unixmachineLv 41 decade ago
This is one of those classes where your grade looking back is always surprising.