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Algebra 1/2 Questions?

I have two algebra questions that I need help with.

1) How do you solve equations where a whole number is be subtracted from a variable and it is over a whole number.

(i.e. m-12/10 = m+4/11)

2) I just don't understand this problem:

Solve a/b x - c = 0 for x.

Please give me the steps and answer not just the answer! Thank you.

9 Answers

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  • 1 decade ago
    Favorite Answer

    1) (m-12)/10 = (m+4)/11

    you need to get rid of the whole numbers at the bottom, so you find the LCM (least common multiple) between the two whole numbers, which is 110(for 10 x 11 = 110).

    so you get

    -->110(m-12)/10=110(m+4)/11 , which simplifies into

    -->11(m-12)=10(m+4)

    now open parenthesis, and you get

    -->11m-132=10m+40

    solve for m.

    -->m=172. :D

    2)i'm guessing you meant a/(bx) - c = 0

    so to solve that, you first move c over to the other side and get

    -->a/(bx) = c

    now multiply both sides by bx

    -->a=bcx

    solve for x.

    -->a/(bc)= x

    so x= a/(bc).

    Source(s): i hope i got your equations right..^^ hope that helped!
  • Lotak
    Lv 4
    1 decade ago

    1) can't use your equation since it doesn't actually make sense.

    Lets say you have 5x +5/4 = 2x + 10/6

    Move the variables to one side and the numbers to the other

    5x - 2x = 10/6 - 5/4

    If you have to sum two fractions a/b + c/d, the sum is: (ad+bc)/bd, and if you need to subtract them, replace the + with a -.

    Therefore you have:

    3x = (10*4-6*5)/(6*4)

    3x = (40-30)/24

    3x = 10/24

    x = 10/72

    x = 5/36

    2) I don't really understand this problem either. From what you have written you just need to make x the subject of the formula

    a/b *x = c

    x = cb/a

  • Anonymous
    1 decade ago

    For #1 you need to multiply out whatever's on the bottom first... so

    (m-12)/10 = (m+4)/11

    becomes

    11(m-12) = 10(m+4)

    becomes

    11m-132 = 10m+40

    put m on one side by canceling (subtracting in this case)

    11m(-10m)-132=40

    m-132=40

    then put your numbers on the other side by canceling again (adding in this case)

    m=40(+132)

    m=172

    Now check your work by plugging your answer in

    (172-12)/10 = (172+4)/11

    160/10 = 176/11

    16=16

    Success.

  • 1 decade ago

    1)

    (m-12)/10 = (m+4)/11

    the common denominator is 110 - multiply by 110

    11(m-12) = 10(m+4)

    11 m - 132 = 10 m + 40

    m = 172

    2)

    a/ b x - c = 0

    add c to both sides

    a/ b x = c

    multiply by b

    a x = b c

    divide by a

    x = b c / a

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  • holdm
    Lv 7
    1 decade ago

    multiply both sides by the least common denominator to get rid of fractions.

    isolate the variable by the appropriate addition/subtraction

    (m-12)/10 = (m+4)/11

    multiply both sides by 110

    11(m-12) = 10(m+4)

    11m - 132 = 10m + 40

    m = 172

    a/b x - c = 0 <multiply both sides by b>

    ax - bc = 0 <add bc to both sides>

    ax = bc <divide both sides by a>

    x = cb/a

  • 1 decade ago

    1. cross multiply

    move all the variables around so that x is by itself

  • 1 decade ago

    It's least common multiple! 8)

  • 1 decade ago

    Simply isolate X

    a/b x - c = 0

    Add c to both sides

    a/b x = c

    Now to get rid of fractions, multiply by the reciprocal.

    (b/a)(a/b) x = (b/a)(c)

    Leaves you with...

    x = (b/a)(c)

    Hope this is right.

  • 1 decade ago

    cross multiply

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