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Algebra 1/2 Questions?
I have two algebra questions that I need help with.
1) How do you solve equations where a whole number is be subtracted from a variable and it is over a whole number.
(i.e. m-12/10 = m+4/11)
2) I just don't understand this problem:
Solve a/b x - c = 0 for x.
Please give me the steps and answer not just the answer! Thank you.
9 Answers
- 1 decade agoFavorite Answer
1) (m-12)/10 = (m+4)/11
you need to get rid of the whole numbers at the bottom, so you find the LCM (least common multiple) between the two whole numbers, which is 110(for 10 x 11 = 110).
so you get
-->110(m-12)/10=110(m+4)/11 , which simplifies into
-->11(m-12)=10(m+4)
now open parenthesis, and you get
-->11m-132=10m+40
solve for m.
-->m=172. :D
2)i'm guessing you meant a/(bx) - c = 0
so to solve that, you first move c over to the other side and get
-->a/(bx) = c
now multiply both sides by bx
-->a=bcx
solve for x.
-->a/(bc)= x
so x= a/(bc).
Source(s): i hope i got your equations right..^^ hope that helped! - LotakLv 41 decade ago
1) can't use your equation since it doesn't actually make sense.
Lets say you have 5x +5/4 = 2x + 10/6
Move the variables to one side and the numbers to the other
5x - 2x = 10/6 - 5/4
If you have to sum two fractions a/b + c/d, the sum is: (ad+bc)/bd, and if you need to subtract them, replace the + with a -.
Therefore you have:
3x = (10*4-6*5)/(6*4)
3x = (40-30)/24
3x = 10/24
x = 10/72
x = 5/36
2) I don't really understand this problem either. From what you have written you just need to make x the subject of the formula
a/b *x = c
x = cb/a
- Anonymous1 decade ago
For #1 you need to multiply out whatever's on the bottom first... so
(m-12)/10 = (m+4)/11
becomes
11(m-12) = 10(m+4)
becomes
11m-132 = 10m+40
put m on one side by canceling (subtracting in this case)
11m(-10m)-132=40
m-132=40
then put your numbers on the other side by canceling again (adding in this case)
m=40(+132)
m=172
Now check your work by plugging your answer in
(172-12)/10 = (172+4)/11
160/10 = 176/11
16=16
Success.
- Davis PLv 71 decade ago
1)
(m-12)/10 = (m+4)/11
the common denominator is 110 - multiply by 110
11(m-12) = 10(m+4)
11 m - 132 = 10 m + 40
m = 172
2)
a/ b x - c = 0
add c to both sides
a/ b x = c
multiply by b
a x = b c
divide by a
x = b c / a
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- holdmLv 71 decade ago
multiply both sides by the least common denominator to get rid of fractions.
isolate the variable by the appropriate addition/subtraction
(m-12)/10 = (m+4)/11
multiply both sides by 110
11(m-12) = 10(m+4)
11m - 132 = 10m + 40
m = 172
a/b x - c = 0 <multiply both sides by b>
ax - bc = 0 <add bc to both sides>
ax = bc <divide both sides by a>
x = cb/a
- 1 decade ago
Simply isolate X
a/b x - c = 0
Add c to both sides
a/b x = c
Now to get rid of fractions, multiply by the reciprocal.
(b/a)(a/b) x = (b/a)(c)
Leaves you with...
x = (b/a)(c)
Hope this is right.