how to solve -4(x+2)=20?

-4(x+2)=20

-4x-8=20

-4x=20+8=28

-x=7

x=-7

:)

start by multiplying out the brackets

-4x-8=20 (remember it is -4 outside the bracket and minus x a plus is a minus)

you now have to do the same to both sides of the equation

add 4x

-8=4x+20 (by doing this you are making x positive which is the best thing to do)

-20

-28=4x

divide by 4

x=-7

Multiply through the bracket to get -4x -8 = 20

-4x = 20 + 8

-4x = 28

4x = -28

x= -7

Step one: distribute the -4 into the parenthesis.

-4x - 8 = 20.

Step two: add 8 to both sides.

-4x = 28.

Step three: divide each side by -4.

x = -7.

solve -4(x+2)=20;

divide both sides by -4;

x+2 = -5

then subtract 2 from both sides;

x = -5 -2

answer; x = -7

Why did the r tard above just give the answer and not explain?

1.) distribute the -4 ------> -4x + -8 = 20

2.) Add +8 to both sides ------> -4x = 28

3.) Divide by -4 both sides ----------> x = -7

Multiply each bit in the brackets...

-4x-8=20

Add 8 to each side.

-4x=28

Divide by -4.

x=28/-4

Simplify.

x=-7

-4x - 8=20

-28 = 4x

x = -7

-4(x+2)=20

-4x-8=20

-4x=20+8

x=28/-4

x= -7

subtract 2 from 20, then divide -4 and 18

it should equal -.2