How to pass an array of string as pointers to a funtion?

Question

For example i have one function          void function(how to pass array of string as pointers?)
I have an array of program id  for example  i.e,P30234,P30324,P34253, and i want to pass these values to the function i mentioned above.Show me how to point to these array, how to pass them as a pointer in function. 

and also how do you loop it to access each string at a time. Don't just explain in words, I need answers as  examples. Thanks alot.

annapoorani_am04 · Accepted Answer

Here's how to prototype and call functions with arrays, references and
pointers.

// one dimension with pointer
void function(int *a);
int array[10];
function(array);

// two dimensions with pointer
void function(int (*a)[20]);
int array[10][20];
function(array);

// three dimensions with pointer
void function(int (*a)[20][30]);
int array[10][20][30];
function(array);


// one dimension with reference
void function(int (&a)[10]);
int array[10];
function(array);

// two dimensions with reference
void function(int (&a)[10][20]);
int array[10][20];
function(array);

// three dimensions with reference
void function(int (&a)[10][20][30]);
int array[10][20][30];
function(array);



If your 2d array is dynamic then you need to allocate some memory for it and
use pointers. E.g.

void function(int** a);

int **array;
array = new int*[size];
for (int i = 0; i < size; ++i)
array[i] = new int[size];
function(array);

melancon · Answer

seem into the "new" operator because it pertains to arrays, then use it to allocate a clean character array for each get entry to in an array of regulations-to-char. this would artwork: char* sentence[ 20 ]; .... sentence[ i ] = new char[ one hundred ]; // undecided of the syntax right here. desire that helps.

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How to pass an array of string as pointers to a funtion?

2 Answers