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3 1/2 times as many guests arrived as expected. If 105 guests were unexpected, how many guests were expected?
6 Answers
- 1 decade ago
42.
Let e = expected guests and u = unexpected guests.
3.5e = u + e (we are told the total number of guests is 3.5 times the expected)
We are also told the unexpected (u) numbered 105. Substituting 105 for u, the equation becomes:
3.5e = 105 + e, or
2.5e = 105, or
e= 42
So, they expected 42 and another 105 unexpected arrived, for a total of 147 guests.
- Anonymous1 decade ago
30
- Randy PLv 71 decade ago
x guests were expected.
3.5x guests arrived
Of these 3.5x, since x were expected, then 3.5x - x = 2.5x were unexpected. So 2.5x = 105
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