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help me find a value for p=a^3 when a=70.00±0.005 meters?

And also to calculate the maximum error in this answer.

Thanks..!!

1 Answer

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  • 1 decade ago
    Favorite Answer

    Since we cannot get the certain answer in this one, the answer is going to be interval.

    The minimum value of a=69.995, and maximum is a=70.005

    p(69.995) = 342926.505249875

    p(70.005) = 343073.505250125

    p interval = [342926.505249875; 343073.505250125]

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