physics numerical problem vector?

I'll show you how to do the first one.

When you need to get C=A+B, add the vectors

Therefore, C=2i+3j+3i-4j=5i-j

Now that you have 5i-j=C, the magnitude is the square root of the sum of the squares,

so take the square root of((5^2)+(-1^2)), which will be the square root of 26 which is equal to 5.1.

For the angle, do the tan(inverse) of the |sin/cos|=tan(inverse) of |1/5|=11.3

Since the coordinates are positive 5 and NEGATIVE 1, your angle of 11.3 degree is actually below the x axis.

If you draw this out, your x coordinate is 5 units in the positive xdirection, and your y coordinate is 1 unit in the negative y direction. Since this is in the negative coordinate region, which is Quadrant 4, you need to subtract that angle of 11.3 from the overall angle of 360 degrees (number of degrees in a circle). This will give you an answer of 349 degrees.

Best of luck.

Shoot me an email if you need anymore help.

ask your professor.