How can I solve and what is the answer to this simultaneous equation?

To start off we can let y = 4 - 2x from the second equation and then plug it into the first equation. In doing this we obtain

4x - 3(4 - 2x) = 13

4x - 12 + 6x = 13

10x - 12 = 13

10x = 25

x = 25 / 10 or x = 5 / 2

To find y, you can use either equation or just simply use y = 4 - 2x. Given that x = 5 / 2, it follows that y = 4 - 2(5 / 2) = -1

So x = 5 / 2 and y = -1 or in coordinates (5 / 2, -1). This is the point where the two lines intersect.

Taking the bottom equation 2x+y=4

we get y=4-2x

Substituting this into first equation we get

4x-3(4-2x)=13

4x-(12-6x)=13

4x-12+6x=13

10x-12=13

10x=25

x=2.5

Substituting this value into the second equation you get

2x2.5+y=4

5+y=4

y=4-5

y=-1

Hold on a min, Ill work it out...ill post an answer soon!

Okay this is my final answer after like 10 attempts

x=2.5, 1.5 and y= -1, 1