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Algebra question... please help?
A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration.
How many liters of each solution must be mixed to obtain 60 liters of a 33% solution?
? liters of the 40% solution and ? liters of the 25% solution must be mixed to obtain a 33% solution.
I am not sure how to set this problem up. Please help, thank you!
2 Answers
- 1 decade ago
Clearly You can let x + y = 60, and the other knowns are the concentrations represented by
the equation 0.4 x + 0.25 y = 0.33 (x + y) = 19.8 by substitution of (x +y). Now then let
0.4 (60 - y) + 0.25 y = 19.8 , so y = 28 and x = 32, both in liters.
- 1 decade ago
Let, x lit of the 1st and y lit of the 2nd must be mixed.
then, x + y = 60 -------------------- (1)
x*40/100 + y*25/100 = 60*33/100
8x + 5y = 396 ---------------------(2)
solving (1) and (2), we get, x = 32, y = 28