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Happy
Happy asked in Science & MathematicsMathematics · 1 decade ago

Algebra 2 (square roots)?

I have a question in my algebra II class and I can't figure out how to do it, can someone please help me or give me a website that i could go to. The question is: f(x) = square root of 48-6x, my teacher wants to know what the domain of the square root is?

4 Answers

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  • s k
    Lv 7
    1 decade ago

    You can only take the square root of non-negative numbers, so:

    48 - 6x ≥ 0

    -6x ≥ -48

    6x ≤ 48

    x ≤ 8

  • Viran Abeysiriwardhana
    1 decade ago

    f(x)=sqrt 48-6x

    any sqrt must be more than or equal to 0 since negatives doesnt have roots...

    so, if 48-6x>=0

    -6x>=-48 cancel the -

    6x>=48

    divide both sides by 6

    x>=8

    the domain should be x>=8

  • shipe
    Lv 4
    5 years ago

    permit's evaluate, I do your homework, get 10 sides that are completely ineffective and to boot you get cheated out of an instruction. guy there is not any approach every physique is going to win in that commerce. Will you be offering $a hundred,000 for anybody to take your test for you???

  • Como
    Lv 7
    1 decade ago

    f ( x ) = √ (48 - 6x )

    Thus

    48 - 6x ≥ 0

    48 ≥ 6x

    x ≤ 8

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