Head and Tail Statistic question?

Question

A bent coin turns up heads with probability .62 .    the coin is tossed 12 times 

a) number of ways that ne may arrange 4 letters H and 3 letters T into a line ?

is it C(12,4)+C(12,3)?

b) what is the probability of sequence HHHH TTT
is it C(12,4)* (.62)^4*(1-.64)^8   + C(12,3)*(1-.62)^3*(.62)^9?

c) what is probability of sequence HHHTHTT
d) The aggregate probability of all sequences that have four H and three T
Thank you . I m so bad at probability i need your help

M3 · Accepted Answer

i'm afraid whatever ans you hv given are incorrect
and i'm taking it that the coin was tossed SEVEN times
else the q's don't seem to make any sense

qa
# of arrangements = 7c4 

qb
since one specific sequence has been given,
reqd. probability 
= .62^4 *.38^3

qc
again, reqd. probability
= .62*3 * .38 * .62 * .38^2
= .62^4 * .38^3, as for qb

qd
multiply by the # of possible sequences
7c4 * .62^4 * .38^3

rudick · Answer

it particularly is probably no longer lots of something which you practice... particularly, you're given this as a certainty. I recommend, the coin became designed to return up heads basically as oftentimes as tails. it particularly is in certainty random. 50% this, 50% that. it particularly is while in comparison with "weighted" funds, or "weighted" cube, that are bodily designed to be unfair. the closest you are able to come to a evidence is by tossing a coin interior the air a gaggle of cases. in case you do one hundred tosses, approximately 50 would be heads (yet no longer precisely, many times.) in case you do one thousand tosses, of 5000, of a million tosses, you will catch up with to 50/50. (The regulation of extensive numbers.)

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Head and Tail Statistic question?

2 Answers