Solve using system of linear equations.?

1) Start out by adding 2 of the three (doesn't matter any) equations to solve for a variable while canceling out the other.

There are two ways you can do it. Adding or subtracting. I prefer adding, so here it goes:

- Set it up like this:

02x - 4y +6z = 48

+ 3x + 2y - 2z = -13

--------------------------

answer right here

- Then try an multiply one of the equation (or both) to cancel out one variable. Looks like i can multiply the second equation by 2 so when (-4y) + 2(2y) = (-4y)+(4y) = 0.

2x - 4y +6z = 48

+ (3x + 2y - 2z = -13) x 2

------------------------------------

answer right here

-It becomes

02x - 4y +6z = 48

+ 6x + 4y - 4z = -36

-----------------------------

8x + 0 + 2z = 22

8x + 2z = 22 (***********)

Now that you've eliminated y, try and find another equation that only has x and y like the above.

(3x+2y-2z=-13) x 5

+ (4x+5y-8z=-55) x 2

-------------------------------

answer right here

becomes:

15x - 10y - 10z = -65

+ 8x +10y - 16z = -110

-------------------------------

7x + 0 - 6z = 45

7x -6z = 45 (********)

Use the two stared equation (*****) add them up to eliminate further.

8x + 2z = 22

+ 7x -6z = 45

----------------------------

becomes:

(8x + 2z = 22) x 3

+ (7x -6z = 45) x1

----------------------------------

becomes:

24x + 6z = 66

+ 7x - 6z = 45

----------------------------

17x + 0 = 21

17x = 21

x = 21/17

And you do the same with other variables to find x and y.

Ugh, I know....I suck at explaining so you might not understand at all

for first one

( 21/17 , -39/17 , 103/17 )

and 2nd

( -4 /7 /3 )

using gauss algoritmus