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Trig Equations help...?

sin4x + 2sin2x = 0

I have to find all exact solutions. How should i start?? thanks

Update:

Nothing is being raised to any power.

Just

Sin(4x) + 2 Sin(2x) =0

3 Answers

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  • huet
    Lv 4
    1 decade ago
    Favorite Answer

    = 2Sin2xCos2x +2Sin2x =0 because sin4x=2sin2xcos2x

    2sin2x(cos2x+1) =0 the following can happen:

    sin2x=0 => 2x=0, Pi, 2Pi or x=0, Pi/2, Pi

    cos2x+1 = 0 => cos2x=-1 => 2x=Pi => x=Pi/2

    Then all solutions are: x=0, Pi/2, Pi

  • 1 decade ago

    is this sin^4 x + 2 sin^2 x = 0 or sin^4 x + 2 sin 2x = 0 or sin 4x + 2 sin^2 x = 0 or sin 4x + 2 sin 2x = 0 ??

    Source(s): my brain
  • 1 decade ago

    sin (4x) + 2 sin (2x) = 0

    because sin (2theta) = 2 sin (theta). cos (theta) , this is an identity of trignometry

    {2sin(2x)* cos(2x)} +2 sin( 2x)= 0

    2 sin(2x){cos (2x) + 1}=0

    Therefore

    sin 2(x) =0 and cos (2x) = -1

    when sin(2x) = 0

    2x = 0,180, 360, 540 .......................degrees

    x = 0,90,180, 270, 360..............degrees.........................Ans

    when

    cos(2x) = -1

    2x = 180 degrees and 540 degrees

    x = 90, 270.............degrees..................Ans

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