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Calc 2 average value question?
this is for my calc 2 homework. I don't have the slightest idea on how to do it.
A ball is thrown in the air vertically from ground level with initial velocity 24 ft/s. Find the average height of the ball over the time interval extending from the time of the ball's release to its return to ground level. Recall that the height at time t is give by the formula below.
h(t) = 24t - 16t2
Thank you for any help
1.) Calculate the average value of the function below over the interval [-1, 3].
f(x) = x2
2.)A mineral deposit along a strip of length 10 cm has density given below in g/cm for 0 ≤ x ≤ 10. Calculate the total mass of the deposit.
s(x) = 0.01x(10 - x)
h(t) = 24t - 16t2 should be h(t) = 24t - 16t^2....my apologies, cut and paste does have its disadvantages as well. thanks again
1 Answer
- johnLv 41 decade agoFavorite Answer
set h=0 to solve for t. integrate h(t) from 0 to time it hits the ground. then set it equal to 1/2. then solve for t to get time at which height is average. then plug it in to original equation to get height.
ireadlots- that is the average height between min and max height, but not the average height over TIME which is what he is asking.
