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can somebody explain this to me?
I got this as an answer on a previous post, and one thing doesn't make sense---where did the 24y come from?
2y^2 +13y -132 = 0
2y^2 + 24y - 11y - 132 = 0 2y(y + 12) -11(y + 12) = 0
(2y - 11) (y + 12) = 0
2y - 11 = 0
2y = 11
y = 11/2
y = 5 1/2
y + 12 = 0
y = -12
1 Answer
- Anonymous1 decade agoFavorite Answer
its something called factor by grouping
typical equation
ax^2+bx+c=0
first you multiply the "a" and the "c" together
next you have to find two that when multiplied together equal the number acquired in the first step "a*c", but you also have to make sure that when those numbers are added together they equal "b"
So really they got the 24y and the -11y by trial and error.
And if you notice 24y -11y= 13y which is equal to their original "b". Also 24*-11= 2*-132
Source(s): Math tutor