how do you solve this with algebra equations?

x(1/2)(2/3)(3/4)-1=2

6/24x -1 = 2

6/24x = 3

x=3(24/6)

x=24/2

x=12

what is "left"

after nadia 1/2 of x is left

after dani 2/3 of 1/2 of x is left

after jordon 3/4 of 2/3 of 1/2 of x is left

after mackenzie 3/4 of 2/3 of 1/2 of x -1

after everyone takes their cookies there are 2 left

x(1/2)(2/3)(3/4)-1=2

nadia took 6

dani took 2

jordan took 1

mackenzie took 1

Think about what fraction is LEFT each time.

Start with x

After nada, there's 1/2 left x/2 left

After dani there's 2/3 left x/2 * 2/3 = x/3 left

after jord theres 3/4 left x/3 * 3/4 = x/4 left so a quarter of the original amount

x/4 - 1 = 2

x/4 = 3

x = 12

if N is the number before Nada takes half and

D is the number before Dani takes 1/3 and

J is the number before Jordan takes 1/4 and

M is the number befor MacKenzie takes 1

then

2 cookies left

M = 2 + 1 = 3

J-J/4 = 3/4 J = M =3

J = 4

D - D/3 = 2D/3 = 4

D = 6

N - N/2 = N/2 = 6

N = 12