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physics homework help?

A car traveling at vo = 34 m/s stops smoothly (that is, its deceleration is constant) over a distance of d = 164 m.

What is its acceleration during the time it is stopping?

I'm confused on what equation I should be using?

1 Answer

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  • Cool
    Lv 5
    1 decade ago
    Favorite Answer

    v^2 - u^2 = 2as

    0^2 - 34^2=2xax164

    328a=-1156

    a=-1156/328= - 3.524m/s^2

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