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equations to form paralleogram?
i have to write equations for 4 lines that intersect to form sides of a parallelogram.. then do the same for 3 lines to form sides of a triangle.
i tried using my graphing calc to help but for the parall. i get 2 perpendicular graphs.... is that the answer? i also have to justify my answers
been a long time since i have done much math
2 Answers
- MathMan TGLv 71 decade agoFavorite Answer
Start with any old line:
y = 2x + 4
then you want a parallel line,
so it too will have slope of 2:
y = 2x + 7
Then you want lines with different slopes.
Negatives might be a good idea ... how about -4 ?
To make things simple, use the same y-intercepts.
y = -4x + 4
and one more with the same slope
y = -4x + 7
There ya go!
The corners of the parallelogram are at
.... (0, 7)
. . ./ . . \
. . / . . . .\
(-1/2, 6) . \
.. \ . . . . . (1/2 , 5)
. ..\ . . . . ./
. . .\ . . . /
.... (0, 4)
For the triangle, use the top half of the parallelogram.
y = 2x + 7 and y = -4x + 7
and
the line from (-1/2, 6) to (1/2, 5)
Slope = (5 - 6) / (1/2 - (-1/2) = -1 / 1 = -1
y = -x + b
6 = 1/2 + b
b = 5.5
The equation is
y = -x + 5.5