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equations to form paralleogram?

i have to write equations for 4 lines that intersect to form sides of a parallelogram.. then do the same for 3 lines to form sides of a triangle.

i tried using my graphing calc to help but for the parall. i get 2 perpendicular graphs.... is that the answer? i also have to justify my answers

Update:

been a long time since i have done much math

2 Answers

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  • 1 decade ago
    Favorite Answer

    Start with any old line:

    y = 2x + 4

    then you want a parallel line,

    so it too will have slope of 2:

    y = 2x + 7

    Then you want lines with different slopes.

    Negatives might be a good idea ... how about -4 ?

    To make things simple, use the same y-intercepts.

    y = -4x + 4

    and one more with the same slope

    y = -4x + 7

    There ya go!

    The corners of the parallelogram are at

    .... (0, 7)

    . . ./ . . \

    . . / . . . .\

    (-1/2, 6) . \

    .. \ . . . . . (1/2 , 5)

    . ..\ . . . . ./

    . . .\ . . . /

    .... (0, 4)

    For the triangle, use the top half of the parallelogram.

    y = 2x + 7 and y = -4x + 7

    and

    the line from (-1/2, 6) to (1/2, 5)

    Slope = (5 - 6) / (1/2 - (-1/2) = -1 / 1 = -1

    y = -x + b

    6 = 1/2 + b

    b = 5.5

    The equation is

    y = -x + 5.5

  • 6 years ago

    feel the equation, be the equation -Gandalf 2015

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