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Does this need simplification?
[4(1+sin(2t))]cos{^3}(t) +
[-4cos(2t)]sin{^3}(t) +
[2T{^(-2)}(1
+sin(2t))sin(2t)]cos{^2}(t) +
[-2(1+sin(2t))]cos(t) +
[2cos(2t)]sin(t) +
[2T{^(-2)}(1
+sin(2t))cos(2t)]cos(t)sin(t) +
[-4T{^2}]cos{^2}(t)sin{^2}(t) +
[T{^(-2)}(1+cos{^2}(2t))] = 0
I don't need numerical solutions; I've got those already.
Can anyone suggest a more concise form in terms of only
circular functions of t, without the 2t terms ?
1 Answer
- Stacy PLv 41 decade agoFavorite Answer
Yes. You should use the double angle identities. See the link. Once everything is in terms of t you might be able to simplify further.
sin(2t) = 2*sin(t)*cos(t)
cos(2t) = cos{^2}(t) - sin{^2}(t)
Hope this helps!