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Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Pre-Calculus problem, please help!?

Find the length of the arc on a circle with a radius of 12cm interpreted by a central angle of 105 degrees. Round your answer to the nearest hundredth of an inch.

a) 21.78 cm

b) 21.99

c) 22.06

d) 24.68

e) none of these

(Also, can you guys explain to me how you found the answer. I have an exam next week & i don't wanna fail.)

Update:

Sorry, all those other ones are 'cm' too.

7 Answers

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  • 1 decade ago
    Favorite Answer

    The arc length of a circle is always the radians of the angle that it makes with its endpoints times the radius. So in this case, the arc length of the circle with a radius 12 cm and a central angle of 105 degrees, (written in radians, which is crucial for calculations, is (105/360)*2*pi) or 1.8326 radians, is equal to 1.8325*12 cm = 21.9911 cm, or about 21.99 cm

    So choice b :D

    Always good to remember that the length of the arc is just the radius of the circle times the angle that the arc makes (in radians, nor degrees!) :D

  • 1 decade ago

    An arc is essentially a portion of the total circumference of the circle. In this case we only have 105 degrees, therefore it is (105 / 360) or 29.2% of a full circle. The circumference of a full circle is equal to pi * diameter, so we can find the arc length by multiplying this by the percentage we have.

    ArcLength = (105 / 360) * pi * d = 0.292 * 3.14 * 24 = 21.99cm

  • heyner
    Lv 4
    4 years ago

    this is the thank you to remedy utilising row-cut back x + y + z = 7 3x - 2y + z = 3 x + 6y + 3z = 25 a million a million a million | 7 3 -2 a million | 3 a million 6 3 | 25 R2 = R2 - 3 * R3 a million a million a million | 7 0 -20 -8 | -seventy two a million 6 3 | 25 R3 = R3 -R1 a million a million a million | 7 0 -20 -8 | -seventy two 0.5 2 | 18 R3 = R3 + a million/4 * R2 a million a million a million | 7 0 -20 -8 | -seventy two 0 0 0 | 0 R1 = R1 + a million/20 * R2 a million 0 .6 | 3.4 0 -20 -8 | -seventy two 0 0 0 | 0 R2 = -R2/20 a million 0 .6 | 3.4 0 a million .4 | 3.6 0 0 0 | 0 So the ideal constraints are that: x + .6z = 3.4 y + .4z = 3.6 case in point, recommendations incorporate: x = a million a million + .6z = 3.4 .6z = 2.4 z = 4 y + .4z = 3.6 y + a million.6 = 3.6 y = 2 x = a million, y = 2, z = 4 x = 2 2 + .6z = 3.4 .6z = a million.4 z = 2.33.. y + .4(2.33..) = 3.6 y = 2.sixty six x = 2, y = 2.sixty six, z = 2.33

  • Anonymous
    1 decade ago

    Arc length = radius * radians

    Change degrees to radians . 105 / 180 * Pi

    105 degrees = 1.83 radians

    1.83 x 12 = 21.99

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  • JOS J
    Lv 7
    1 decade ago

    P = 2 Pi 12. (105/360)

    P = 21.9911

    b) 21.99

  • Hankm
    Lv 7
    1 decade ago

    105/360 = 0.2917 the arc =.2917 times the circumference

    circumference = 2*PI*R

    arc =.2917*2*PI*12 = 22cm

  • ?
    Lv 7
    1 decade ago

    c=2pi*r

    2pi=360 degrees

    so you have to substitute the pi value for 105 degrees

    c=2pi(105/360)*12

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