if i have a 4% decrease in population every year, from 1000, what is my formula?

= 1,000(1 - 0.04)° where ° is number of years

= 1,000(0.96)°

Answer: 1,000(0.96)°

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= 1,000(0.96)¹°

= 1,000(0.664832636)

= 665

Answer: 665

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= 1,000(0.96)¹⁶

= 1,000(0.520402925)

= 520

Answer: 520

Every year the population decreases by 4%, leaving 96% remaining, so you have 0.96 times the previous year.

So if you start with 1000:

After t years you have 1000 * 0.96^t

After 10 years you have 1000 * 0.96^10 =~ 664

After 16 years you have 1000 * 0.96^16 =~ 520

1000(0.96)^10 = the 10th year

1000(0.96)^16 = the 16th year

Hope this helps!

P =P1000*0.96^Y

where P1000 = population in year 1000

Y = number of years snice 1000

P1010 = P1000 * 0.96^10 = 0.665* P1000

P1016 = P1000 * 0.96^16 = 0.520*P1000

A = 1000*(0.96)^t

Nt=N0*e ^(r*t)

Nt = Future Population

N0 = Starting population

r = growth rate

t= number of years.