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how to calculate the ph of a solution?
The Ph of aqueous 0.10 M nitrite ion is 8.17. What is the Kb of this base?
If you could show your work, with how you got it i would great appreciate it!
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- Dr.ALv 71 decade agoFavorite Answer
NO2- + H2O < = > HNO2 + OH-
pOH = 14 - 8.17 = 5.83
[OH-]= 10^-5.83=1.48 x 10^-6 M = [HNO2]
Kb = [HNO2][OH-]/ [NO2-] = ( 1.48 x 10^-6)^2/ 0.10=2.19 x 10^-11
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