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evaluate (log base 6 of 12) + (log base 6 of 8) - (2log base 6 of 4)?
i need help, i don't know what to do with the "2" on the last part. (2log base 6 of 4). thanks
3 Answers
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- Anonymous1 decade ago
i can be wrong, but there was something like Xlog base 6 of 4 = log base 6 of 4^x ?
according to this, it will be like log base 6 of 16
- ComoLv 71 decade ago
Let log be log to base 6
log 12 + log 8 - 2 log 4
log 96 + log 4^(-2)
log [ 96 / 16 ]
log 6
1
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