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The numbers 2,x,y are three consecutive terms of a geometric sequence and x,30,y are three consecutive?
terms of an arithmetic sequence. find the positive value of x and the corresponding y value.
Thank you MexhEng2
I may have spent a few hours on this sum!
Addendum:
For
x² + 2x - 120 = 0
I would facotorise directly
(x+12)(x-10) = 0
x = -12 or x = 10, etc.
2 Answers
- MechEng2030Lv 71 decade agoFavorite Answer
From the first sequence:
y/x = x/2-->(1)
From the second sequence:
30 - x = y - 30
60 - x = y-->(2)
Plugging (2) into (1):
(60 - x)/x = x/2
120 - 2x = x²
x² + 2x - 120 = 0
(x + 1)² - 121 = 0
x = +/- 11 - 1
x = 10 and x = -12
Positive value of x is 10.
Corresponding y -val is 50
- Anonymous4 years ago
(5x + 2)/(x + 4) = (x + 4)/(x - 2) (5x + 2)(x - 2) = (x + 4)^2 5x^2 - 8x - 4 = x^2 + 8x + sixteen 4x^2 - 16x - 20 = 0 x^2 - 4x - 5 = 0 (x - 5)(x + a million) = 0 x = 5 or x = -a million so which you have (x = 5) 3, 9, 27 which provides a ratio of three:a million for each consecutive term or (x = -a million) -3, 3, -3 which provides a ratio of -a million:a million for each consecutive term.
