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Can you help me with Hardy-Weinberg Problems?
I want more general help than with a specific problem. I don't really understand how to do HW problems when they give you phenotype.
For example: if it tells me that 360 out of 1,000 in a population display the recessive phenotype, how would I find the numbers of individuals expected to be homozygous dominant and heterozygous for the trait?
I tried making the 360 => .36 in the P+Q=1 equation, but then I don't know how to find the 2PG (for the hets) because the numbers will no longer add up to 1 in the p^2+2pq+q^2 equation. Is .36 really the q^2? And then I have to find normal q by square rooting? Or am I on entirely the wrong track?
Also: if they tell me that 510 out of 1,000 show the dominant phenotype, how do I find the numbers of individuals for each genotype?
Please help tell me HOW to do these problems and not just what the answers are...thank you!
1 Answer
- Anonymous1 decade agoFavorite Answer
360 out of 1000 represents the q^2 in the equation so q= square root of .36 = .6
p+q=1
q = .6 so p must be .6
p^2+2pq+q^2 would be .16 + .48 + .36 = 1
and for your supplementary question:
510 out of 1000 show dominant, so 490 must show recessive
again, q = sqr rt .49 = .7 so p must be .3
p^2+2pq+q^2 would be .09 + .42 + .49
So out of 1000, 90 would be homozygous dominant, 420 would be heterozygous and 490 recessive.
90 + 420 = 510 dominant
OK?
John H