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can somebody factor this x^32-1?
hi i was wondering if somebody could take me step by step on how to answer this question. much appreciated
1 Answer
- RobertLv 61 decade agoFavorite Answer
You have the difference of two squares, so
(x^16 + 1)(x^16 - 1)
The second term is the difference of two squares, so
(X^16 + 1)(x^8 + 1)(x^8 - 1)
The third term is the difference of two squares, so
(X^16 + 1)(x^8 + 1)(x^4 + 1)(x^4 - 1)
The fourth term is the difference of two squares, so
(X^16 + 1)(x^8 + 1)(x^4 + 1)(x^2 + 1)(x^2 - 1)
The fifth term is the difference of two squares, so we finally get
(X^16 + 1)(x^8 + 1)(x^4 + 1)(x^2 + 1)(x + 1)(x - 1) = x^32 - 1