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Mutual Induction Help?

A long, current-carrying solenoid with an air core has 1750 turns per meter of length and a radius of 0.0190 m. A coil of 127 turns is wrapped tightly around the outside of the solenoid. What is the mutual inductance of this system?

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  • 1 decade ago
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    N/L = 1750turns/m

    r = .0190m

    N = 120turns

    your equations:

    phi = BA

    B = (N*i*u)/l

    phi = L*i/N

    N / (N/l) = l

    l = length

    L = mutual induction

    susbstitue (N*i*u)/l for B in phi = BA :

    phi = (N*i*u*A)/l

    set the two phi equal to each other:

    (L*i)/N = (N*i*u*A)/l

    Solve for L:

    L = (N^2*u*A)/l

    Substitue N*(N/l) for l

    L = (N^2*u*A) / (N / (N/l) )

    your answer should be:

    3.39e-4 H

    Sorry I'm a day late, Cam :(

    Source(s): muh brain
  • 4 years ago

    Electromagnetism skill that after contemporary flows by way of a cord then magnetic traces are produced around the present sporting conductor. If the cord is interior the variety of a solenoid then one end will become as north pole and the different as south pole. This phenomenon is standard as electromagnetism. If think we take a magnet in the direction of one in each and every of these solenoid, then the present brought about interior the solenoid might attempt to end the magnet coming in the direction of it. If, in any different case, we eliminate a magnet from the solenoid then the present is brought about interior the different course with a view to draw the receding magnet. So frequently a solenoid desires to be in an unchanging state. If think there be any replace in magnetism then induction occurs as to maintain up the location the comparable. hence the induction interior the variety of electro magnetism is standard to be electromagnetic induction.

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